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The radicand of the function must be greater than or equal to 0 since we cannot take the square root of a negative number.
So we must have
≥ 0
Solving for x we see that x ≥ 1
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(1/3)(x-1) = 0
3*(1/3)(x-1) = 0*3
(x-1)=0
x=1
Thus the domain is all read numbers greater than or equal to 1, interval notation
[1,∞)
Since the function is a square root, the range must be greater than or equal to 0.
(This is the output, or the value of the function)
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Remember we cannot have a negative square root!
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So interval notation for range is
[0,∞)
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